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-27x^2+6x+5=x
We move all terms to the left:
-27x^2+6x+5-(x)=0
We add all the numbers together, and all the variables
-27x^2+5x+5=0
a = -27; b = 5; c = +5;
Δ = b2-4ac
Δ = 52-4·(-27)·5
Δ = 565
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{565}}{2*-27}=\frac{-5-\sqrt{565}}{-54} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{565}}{2*-27}=\frac{-5+\sqrt{565}}{-54} $
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